Take the 2-minute tour ×
Theoretical Physics Stack Exchange is a question and answer site for scientific theorists and academic scholars interested in theoretical, research-level physics. It's 100% free, no registration required.

Heisenberg's uncertainty principle states that: if the x-component of the momentum of a particle is measured with an uncertainty $$\Delta \vec p_x$$ then its x-position cannot, at same time, be measured more accurately than $$\Delta\vec x=\frac {\hbar}{2\Delta\vec p_x }$$ $$\Delta\vec x\Delta\vec p_x \ge \frac {\hbar}{2}$$ what is scientific prove of this principle?


migrated to physics.stackexchange.com by Piotr Migdal Apr 20 '12 at 16:16

This question belongs on our site for active researchers, academics and students of physics.

This is a standard textbook question, so I am moving it to physics.SE. Moreover, when refer to a component of a vector then you drop the arrow. –  Piotr Migdal Apr 20 '12 at 16:15

Browse other questions tagged or ask your own question.